2(3v+2)=4[4v-3(-v-4)]

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Solution for 2(3v+2)=4[4v-3(-v-4)] equation:


Simplifying
2(3v + 2) = 4[4v + -3(-1v + -4)]

Reorder the terms:
2(2 + 3v) = 4[4v + -3(-1v + -4)]
(2 * 2 + 3v * 2) = 4[4v + -3(-1v + -4)]
(4 + 6v) = 4[4v + -3(-1v + -4)]

Reorder the terms:
4 + 6v = 4[4v + -3(-4 + -1v)]
4 + 6v = 4[4v + (-4 * -3 + -1v * -3)]
4 + 6v = 4[4v + (12 + 3v)]

Reorder the terms:
4 + 6v = 4[12 + 4v + 3v]

Combine like terms: 4v + 3v = 7v
4 + 6v = 4[12 + 7v]
4 + 6v = [12 * 4 + 7v * 4]
4 + 6v = [48 + 28v]

Solving
4 + 6v = 48 + 28v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-28v' to each side of the equation.
4 + 6v + -28v = 48 + 28v + -28v

Combine like terms: 6v + -28v = -22v
4 + -22v = 48 + 28v + -28v

Combine like terms: 28v + -28v = 0
4 + -22v = 48 + 0
4 + -22v = 48

Add '-4' to each side of the equation.
4 + -4 + -22v = 48 + -4

Combine like terms: 4 + -4 = 0
0 + -22v = 48 + -4
-22v = 48 + -4

Combine like terms: 48 + -4 = 44
-22v = 44

Divide each side by '-22'.
v = -2

Simplifying
v = -2

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